x^2-4x+22=5

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Solution for x^2-4x+22=5 equation: 



x^2-4x+22=5

We move all terms to the left:

x^2-4x+22-(5)=0

We add all the numbers together, and all the variables

x^2-4x+17=0

a = 1; b = -4; c = +17;
Δ = b2-4ac
Δ = -42-4·1·17
Δ = -52
Delta is less than zero, so there is no solution for the equation

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